(8x+7)(x^2-4x+2)=0

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Solution for (8x+7)(x^2-4x+2)=0 equation: 


Simplifying
(8x + 7)(x2 + -4x + 2) = 0

Reorder the terms:
(7 + 8x)(x2 + -4x + 2) = 0

Reorder the terms:
(7 + 8x)(2 + -4x + x2) = 0

Multiply (7 + 8x) * (2 + -4x + x2)
(7(2 + -4x + x2) + 8x * (2 + -4x + x2)) = 0
((2 * 7 + -4x * 7 + x2 * 7) + 8x * (2 + -4x + x2)) = 0
((14 + -28x + 7x2) + 8x * (2 + -4x + x2)) = 0
(14 + -28x + 7x2 + (2 * 8x + -4x * 8x + x2 * 8x)) = 0
(14 + -28x + 7x2 + (16x + -32x2 + 8x3)) = 0

Reorder the terms:
(14 + -28x + 16x + 7x2 + -32x2 + 8x3) = 0

Combine like terms: -28x + 16x = -12x
(14 + -12x + 7x2 + -32x2 + 8x3) = 0

Combine like terms: 7x2 + -32x2 = -25x2
(14 + -12x + -25x2 + 8x3) = 0

Solving
14 + -12x + -25x2 + 8x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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